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Simplifying 2(3y + -5z + 1) = 2[3y + (-5z) + 1] Reorder the terms: 2(1 + 3y + -5z) = 2[3y + (-5z) + 1] (1 * 2 + 3y * 2 + -5z * 2) = 2[3y + (-5z) + 1] (2 + 6y + -10z) = 2[3y + (-5z) + 1] Reorder the terms: 2 + 6y + -10z = 2[1 + 3y + (-5z)] 2 + 6y + -10z = [1 * 2 + 3y * 2 + (-5z) * 2] 2 + 6y + -10z = [2 + 6y + -10z] Add '-2' to each side of the equation. 2 + 6y + -2 + -10z = 2 + 6y + -2 + -10z Reorder the terms: 2 + -2 + 6y + -10z = 2 + 6y + -2 + -10z Combine like terms: 2 + -2 = 0 0 + 6y + -10z = 2 + 6y + -2 + -10z 6y + -10z = 2 + 6y + -2 + -10z Reorder the terms: 6y + -10z = 2 + -2 + 6y + -10z Combine like terms: 2 + -2 = 0 6y + -10z = 0 + 6y + -10z 6y + -10z = 6y + -10z Add '-6y' to each side of the equation. 6y + -6y + -10z = 6y + -6y + -10z Combine like terms: 6y + -6y = 0 0 + -10z = 6y + -6y + -10z -10z = 6y + -6y + -10z Combine like terms: 6y + -6y = 0 -10z = 0 + -10z -10z = -10z Add '10z' to each side of the equation. -10z + 10z = -10z + 10z Combine like terms: -10z + 10z = 0 0 = -10z + 10z Combine like terms: -10z + 10z = 0 0 = 0 Solving 0 = 0 Couldn't find a variable to solve for. This equation is an identity, all real numbers are solutions.
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